Step 1: Understanding the direction vector of the line. The given line can be expressed as: \[ \vec{r} = \hat{i} + \hat{j} - \hat{k} + \lambda (3\hat{i} - \hat{j}) \] Here, the direction vector of the line is: \[ \vec{d} = 3\hat{i} - \hat{j} \]
Step 2: Condition for perpendicularity. A vector \( \vec{v} \) is perpendicular to \( \vec{d} \) if their dot product is zero: \[ \vec{v} \cdot \vec{d} = 0 \] Let \( \vec{v} = a\hat{i} + b\hat{j} + c\hat{k} \). The dot product is: \[ \vec{v} \cdot \vec{d} = (a\hat{i} + b\hat{j} + c\hat{k}) \cdot (3\hat{i} - \hat{j}) = 3a - b \] For perpendicularity: \[ 3a - b = 0 \quad \Rightarrow \quad b = 3a \quad \cdots (1) \]
Step 3: Using the options to find the correct vector. We substitute the options to check which satisfies \( b = 3a \): For \( \hat{i} + 3\hat{j} + 5\hat{k} \)
(Option \( B \)): \[ a = 1, \, b = 3, \, c = 5 \] Substituting into \( b = 3a \): \[ b = 3 \times 1 = 3 \quad \text{(True)} \] Therefore, this vector satisfies the condition.
Other options do not satisfy \( b = 3a \).
Conclusion: Thus, the required vector is \( \hat{i} + 3\hat{j} + 5\hat{k} \), which corresponds to option \( \mathbf{(B)} \).
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).