Consider the following reaction:
\[ \text{CCl}_4(g) \rightarrow \text{C}(g) + 4 \text{Cl}(g) \quad \Delta H = 1304\text{ kJ} \]
What is $\Delta_{\text{vap}} H^\ominus$ of $\text{CCl}_4(l)$ (in $\text{kJ}\cdot\text{mol}^{-1}$)?
Given: $\Delta_f H^\ominus(\text{CCl}_4(l)) = -135.5\text{ kJ}\cdot\text{mol}^{-1}$, $\Delta_a H^\ominus(\text{C}) = 715\text{ kJ}\cdot\text{mol}^{-1}$, $\Delta_a H^\ominus(\text{Cl}_2) = 242\text{ kJ}\cdot\text{mol}^{-1}$