Question:
Observe the following polymerization reactions I and II: I. $A+B \rightarrow X$ (polymer), II. $C+D \rightarrow Y$ (polymer). In reaction I, monomer (A) reacts with NaOH, and in reaction II, monomer (C) reacts with $NaHCO_3$. What are X and Y respectively?
Observe the following polymerization reactions I and II: I. $A+B \rightarrow X$ (polymer), II. $C+D \rightarrow Y$ (polymer). In reaction I, monomer (A) reacts with NaOH, and in reaction II, monomer (C) reacts with $NaHCO_3$. What are X and Y respectively?
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Identification of functional groups (acidic vs. basic) helps identify monomers in polycondensation.
Updated On: Jun 10, 2026
- Melamine; Glyptal
- Bakelite; Neoprene
- Buna-S; Caprolactam
- Novolac; Terylene
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The Correct Option is A
Solution and Explanation
Step 1: Concept
Polymer synthesis and monomer reactivity.
Step 2: Analysis
Reaction I: Monomer (A) reacts with NaOH (basic). Monomers like melamine are produced from precursors reactive under basic conditions. Reaction II: Monomer (C) reacts with $NaHCO_3$ (weakly basic, acidic functional group). Glyptal is formed from phthalic acid and ethylene glycol; phthalic acid reacts with $NaHCO_3$.
Step 3: Conclusion
The products are Melamine and Glyptal.
Final Answer: (A)
Polymer synthesis and monomer reactivity.
Step 2: Analysis
Reaction I: Monomer (A) reacts with NaOH (basic). Monomers like melamine are produced from precursors reactive under basic conditions. Reaction II: Monomer (C) reacts with $NaHCO_3$ (weakly basic, acidic functional group). Glyptal is formed from phthalic acid and ethylene glycol; phthalic acid reacts with $NaHCO_3$.
Step 3: Conclusion
The products are Melamine and Glyptal.
Final Answer: (A)
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