If the molar masses of Na$_2$S$_2$O$_3$ and I$_2$ are M$_1$ and M$_2$ respectively, then the equivalent weights of Na$_2$S$_2$O$_3$ and I$_2$ in the reaction:
\[
2\,\text{Na}_2\text{S}_2\text{O}_3 + I_2 \rightarrow 2\,\text{NaI} + \text{Na}_2\text{S}_4\text{O}_6
\]
are respectively: