In a photoelectric effect, the kinetic energy of electrons is \(1.3 \times 10^{-19}\,\text{J}\). If work function of the metal is \(2.27\,\text{eV}\), then the frequency (in Hz) of the incident radiation is (\(h = 6.6 \times 10^{-34}\,\text{J s}\), \(1\,\text{eV} = 1.6 \times 10^{-19}\,\text{J}\)).