Question:

Write the IUPAC name of the given complex :

\( \mathrm{K_2[Zn(OH)_4]} \)

Show Hint

Zn is +2 and the complex ion is an anion, so the name is potassium tetrahydroxidozincate(II).
Updated On: Oct 22, 2026
Show Solution
collegedunia
Verified By Collegedunia

Solution and Explanation

Step 1: Understanding the Concept:
In a coordination compound, the cation is named first and then the complex ion. Inside the complex ion, ligands are named before the metal.

Step 2: Split the formula:
The formula is \( \mathrm{K_2[Zn(OH)_4]} \).
The cation is \( \mathrm{K^+} \) (potassium). The complex ion is \( \mathrm{[Zn(OH)_4]^{2-}} \).

Step 3: Find the oxidation state of zinc:
Let the oxidation state of Zn be \( x \). Each \( \mathrm{OH^-} \) carries -1.
\[ x + 4(-1) = -2 \Rightarrow x = +2 \]

Step 4: Build the name:
Four hydroxido ligands give the prefix tetra, so the ligand part is tetrahydroxido.
The complex ion is anionic, so the metal takes the ending -ate: zincate.
The oxidation state goes in brackets after the metal: (II).

Final Answer:
The name is potassium tetrahydroxidozincate(II). \[ \boxed{\text{Potassium tetrahydroxidozincate(II)}} \]
Was this answer helpful?
0
0

Top CBSE CLASS XII Chemistry Questions

View More Questions