To solve the problem, we need to write the IUPAC name of the given complex: [Co(NH₃)₅(CO₃)]Cl.
1. Analyzing the Complex:
The given complex consists of a cobalt (Co) metal ion, ammonia (NH₃) ligands, a carbonate (CO₃²⁻) ligand, and a chloride (Cl⁻) counterion. The ammonia ligands are neutral, while the carbonate ion is a bidentate ligand that is negatively charged, and the chloride ion is an anion that balances the charge of the complex.
2. Naming the Ligands:
In IUPAC nomenclature, the ligands are named first, in alphabetical order, followed by the name of the metal ion. The ligands are: - Ammonia (NH₃) is named "ammine." - Carbonate (CO₃²⁻) is named "carbonato." - The chloride ion (Cl⁻) is named "chlorido."
3. Naming the Metal Ion:
The metal ion is cobalt (Co), and since it has a +3 oxidation state in this complex, we use the Roman numeral III to indicate this. The metal is followed by the suffix "ate" because the complex has a negative charge due to the chloride ion. The metal's name in the complex will be "cobaltate."
4. Putting It All Together:
Now, we can write the full IUPAC name of the complex:
- First, we list the ligands in alphabetical order: "ammine" and "carbonato."
- Then, we name the metal as "cobalt," followed by the oxidation state of cobalt in Roman numerals.
- Finally, we mention the counterion, "chlorido."
Thus, the IUPAC name of the complex [Co(NH₃)₅(CO₃)]Cl is pentamminecarbonatocobalt(III) chloride.
Write IUPAC names of the following compounds and classify them into primary, secondary and tertiary amines.
(i) (CH3 )2CHNH2 (ii) CH3 (CH2 )2NH2 (iii) CH3NHCH(CH3 )2
(iv) (CH3 )3CNH2 (v) C6H5NHCH3 (vi) (CH3CH2 )2NCH3 (vii) m–BrC6H4NH2
Give one chemical test to distinguish between the following pairs of compounds.
(i) Methylamine and dimethylamine
(ii) Secondary and tertiary amines
(iii) Ethylamine and aniline
(iv) Aniline and benzylamine
(v) Aniline and N-methylaniline
Account for the following:
(i) pKb of aniline is more than that of methylamine.
(ii) Ethylamine is soluble in water whereas aniline is not.
(iii) Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
(iv) Although amino group is o– and p– directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.
(v) Aniline does not undergo Friedel-Crafts reaction.
(vi) Diazonium salts of aromatic amines are more stable than those of aliphatic amines. (vii) Gabriel phthalimide synthesis is preferred for synthesising primary amines.