Write IUPAC names of the following coordination entities:
(a) \( [Fe(en)_2Cl_2]^+ \)
(b) \( [Co(NH_3)_4(H_2O)Br]SO_4 \)
(c) \( [Ni(CN)_4]^{2-} \)
To solve the problem, we need to write the IUPAC names of the given coordination entities: (a) \( [Fe(en)_2Cl_2]^+ \), (b) \( [Co(NH_3)_4(H_2O)Br]SO_4 \), and (c) \( [Ni(CN)_4]^{2-} \).
1. Name \( [Fe(en)_2Cl_2]^+ \):
- Central metal: Fe, oxidation state: +3 (since 2 Cl⁻ give -2, total charge +1, so Fe is +3).
- Ligands: en (ethylenediamine, neutral) × 2, Cl⁻ × 2.
- Name ligands alphabetically: ‘en’ (di- for 2) as ethylenediamine, Cl as chloro.
- Complex is cationic, so metal name is iron(III).
IUPAC name: \( \text{Dichloridobis(ethylenediamine)iron(III)} \).
2. Name \( [Co(NH_3)_4(H_2O)Br]SO_4 \):
- Central metal: Co, oxidation state: +3 (Br⁻ gives -1, \( SO_4^{2-} \) gives -2, total charge 0, so Co is +3).
- Ligands in complex: \( NH_3 \) (neutral) × 4, \( H_2O \) (neutral) × 1, Br⁻ × 1.
- Name ligands alphabetically: ammine (\( NH_3 \), tetra- for 4), aqua (\( H_2O \)), bromido (Br⁻).
- Complex is cationic, counter ion is sulfate, metal name is cobalt(III).
IUPAC name: \( \text{Tetraammineaquabromidocobalt(III) sulfate} \).
3. Name \( [Ni(CN)_4]^{2-} \):
- Central metal: Ni, oxidation state: +2 (4 CN⁻ give -4, total charge -2, so Ni is +2).
- Ligands: CN⁻ × 4, named as cyano (but in IUPAC, ‘cyano’ is used, tetra- for 4).
- Complex is anionic, so metal name is nickelate(II).
IUPAC name: \( \text{Tetracyanonickelate(II)} \).
Final Answer:
(a) \( \text{Dichloridobis(ethylenediamine)iron(III)} \), (b) \( \text{Tetraammineaquabromidocobalt(III) sulfate} \), (c) \( \text{Tetracyanonickelate(II)} \).
Write IUPAC names of the following compounds and classify them into primary, secondary and tertiary amines.
(i) (CH3 )2CHNH2 (ii) CH3 (CH2 )2NH2 (iii) CH3NHCH(CH3 )2
(iv) (CH3 )3CNH2 (v) C6H5NHCH3 (vi) (CH3CH2 )2NCH3 (vii) m–BrC6H4NH2
Give one chemical test to distinguish between the following pairs of compounds.
(i) Methylamine and dimethylamine
(ii) Secondary and tertiary amines
(iii) Ethylamine and aniline
(iv) Aniline and benzylamine
(v) Aniline and N-methylaniline
Account for the following:
(i) pKb of aniline is more than that of methylamine.
(ii) Ethylamine is soluble in water whereas aniline is not.
(iii) Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
(iv) Although amino group is o– and p– directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.
(v) Aniline does not undergo Friedel-Crafts reaction.
(vi) Diazonium salts of aromatic amines are more stable than those of aliphatic amines. (vii) Gabriel phthalimide synthesis is preferred for synthesising primary amines.