Concept: Transition metals form metallic crystal lattices (FCC, BCC, or HCP) made of closely packed metal atoms. These lattices naturally contain small empty spaces known as interstitial sites.
Step 1: Understand interstitial sites. When metal atoms arrange in a crystal lattice, small voids are left between them. These voids are called interstitial spaces.
Step 2: Incorporation of small atoms. Small non-metal atoms such as: \[ \text{H, C, N, B} \] can easily occupy these interstitial sites without significantly disturbing the metal lattice.
Step 3: Formation of interstitial compounds. This leads to the formation of interstitial compounds such as: \[ TiC,\ Mn_4N,\ Fe_3H \] These compounds are often non-stoichiometric and retain metallic characteristics.
Step 4: Final conclusion. Transition metals form interstitial compounds because their crystal lattices contain empty interstitial spaces where small atoms can be accommodated.
Write IUPAC names of the following compounds and classify them into primary, secondary and tertiary amines.
(i) (CH3 )2CHNH2 (ii) CH3 (CH2 )2NH2 (iii) CH3NHCH(CH3 )2
(iv) (CH3 )3CNH2 (v) C6H5NHCH3 (vi) (CH3CH2 )2NCH3 (vii) m–BrC6H4NH2
Give one chemical test to distinguish between the following pairs of compounds.
(i) Methylamine and dimethylamine
(ii) Secondary and tertiary amines
(iii) Ethylamine and aniline
(iv) Aniline and benzylamine
(v) Aniline and N-methylaniline
Account for the following:
(i) pKb of aniline is more than that of methylamine.
(ii) Ethylamine is soluble in water whereas aniline is not.
(iii) Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
(iv) Although amino group is o– and p– directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.
(v) Aniline does not undergo Friedel-Crafts reaction.
(vi) Diazonium salts of aromatic amines are more stable than those of aliphatic amines. (vii) Gabriel phthalimide synthesis is preferred for synthesising primary amines.
Write down the electronic configuration of:
(i) Cr3+ (iii) Cu+ (v) Co2+ (vii) Mn2+
(ii) Pm3+ (iv) Ce4+ (vi) Lu2+ (viii) Th4+
Why are Mn2+ compounds more stable than Fe2+ towards oxidation to their +3 state?
What may be the stable oxidation state of the transition element with the following d electron configurations in the ground state of their atoms : 3d3 ,3d5 ,3d8 and 3d4?