Question:
Which of the following represents correct order of oxidizing power of halogens with water?
Which of the following represents correct order of oxidizing power of halogens with water?
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Electronegativity and bond strength dictate the oxidizing power of halogens in aqueous solution.
Updated On: Jun 26, 2026
- I\(_2\) > Br\(_2\) > Cl\(_2\) > F\(_2\)
- Cl\(_2\) > F\(_2\) > Br\(_2\) > I\(_2\)
- F\(_2\) > Cl\(_2\) > I\(_2\) > Br\(_2\)
- F\(_2\) > Cl\(_2\) > Br\(_2\) > I\(_2\)
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The Correct Option is D
Solution and Explanation
Step 1: Recall halogen oxidizing trends.
Oxidizing power decreases down the group due to decreasing electronegativity and bond dissociation energy.
Step 2: Apply to halogens.
F\(_2\) > Cl\(_2\) > Br\(_2\) > I\(_2\)
Step 3: Conclusion.
\[ \boxed{\text{F}_2 \gt \text{Cl}_2 \gt \text{Br}_2 \gt \text{I}_2} \]
Oxidizing power decreases down the group due to decreasing electronegativity and bond dissociation energy.
Step 2: Apply to halogens.
F\(_2\) > Cl\(_2\) > Br\(_2\) > I\(_2\)
Step 3: Conclusion.
\[ \boxed{\text{F}_2 \gt \text{Cl}_2 \gt \text{Br}_2 \gt \text{I}_2} \]
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