Question:

Which of the following is correct?

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Autosomal recessive disorders require two defective alleles to express the disease.
Updated On: Jun 20, 2026
  • Phenylketonuria is an autosomal dominant disorder
  • Color blindness is a sex-linked dominant disorder
  • Thalassemia is an autosomal recessive disorder
  • Cystic fibrosis is an autosomal dominant disorder
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The Correct Option is C

Solution and Explanation

Step 1: Understanding genetic disorder classification.
Genetic disorders are classified based on inheritance patterns such as autosomal dominant, autosomal recessive, and sex-linked traits. These patterns determine how a disease is passed from parents to offspring.

Step 2: Concept of autosomal recessive inheritance.

In autosomal recessive disorders, both alleles must be defective for the disease to express. Carriers with one normal allele usually remain unaffected.

Step 3: Evaluating phenylketonuria.

Phenylketonuria (PKU) is caused by mutation in the gene coding for phenylalanine hydroxylase. It is autosomal recessive, not dominant, making option (1) incorrect.

Step 4: Evaluating color blindness.

Color blindness is a sex-linked recessive disorder located on the X chromosome. It is not dominant, so option (2) is incorrect.

Step 5: Evaluating thalassemia.

Thalassemia results from mutations in globin genes affecting hemoglobin synthesis. It follows autosomal recessive inheritance and requires both alleles to be defective.

Step 6: Evaluating cystic fibrosis.

Cystic fibrosis is also an autosomal recessive disorder caused by mutations in the CFTR gene affecting chloride ion transport. It is not dominant.

Step 7: Final analysis.

Only thalassemia correctly matches autosomal recessive inheritance among the given options.
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