Which is the correct order of acid strength from the following?
To determine the correct order of acid strength among phenol (C_6H_5OH), water (H_2O), and alcohols (ROH), we must consider their ability to donate a proton (H+), which is indicative of acid strength.
Phenol (C_6H_5OH): Phenol is a weak acid but stronger than both water and alcohols. The phenoxide ion, formed after donating a proton, is stabilized by resonance with the benzene ring.
Water (H_2O): Water is less acidic than phenol but more acidic than alcohols. The hydroxide ion formed is stable but lacks resonance stabilization found in phenoxide.
Alcohols (ROH): Alcohols are the weakest acids because the alkoxide ion formed after losing a proton is not stabilized by resonance or significant electronegativity effects.
Order of Acid Strength: The acid strength order based on their ability to donate protons and stabilization of resulting ions is:
C_6H_5OH > H_2O > ROH
This order is due to the resonance stabilization of the phenoxide ion, moderate stability of hydroxide ion, and the lack of stabilization in the alkoxide ion.
Amides are less basic than amines.
Why phenol does not undergo protonation readily?
Match the following carboxylic acids with their pKa values.

A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).