What is crystal field splitting energy? How does the magnitude of\( Δo\) decide the actual configuration of d-orbitals in a coordination entity?
The degenerate d-orbitals (in a spherical field environment) split into two levels i.e., \(e_g\) and \(t_{2g}\) in the presence of ligands. The splitting of the degenerate levels due to the presence of ligands is called the crystal-field splitting while the energy difference between the two levels (\(e_g\) and \(t_{2g}\)) is called the crystal-field splitting energy. It is denoted by \(Δo\). After the orbitals have split, the filling of the electrons takes place. After 1 electron (each) has been filled in the three \(t_{2g}\)orbitals, the filling of the fourth electron takes place in two ways. It can enter the \(e_g\) orbital (giving rise to t2g 3 eg 1 like electronic configuration) or the pairing of the electrons can take place in the \(t_{2g}\) orbitals (giving rise to \(t_{2g}\) 4 \(e_g\) 0 like electronic configuration). If the Δo value of a ligand is less than the pairing energy \((P)\), then the electrons enter the egorbital. On the other hand, if the \(Δo\) value of a ligand is more than the pairing energy \((P)\), then the electrons enter the \(t_{2g}\)orbital.
Write IUPAC names of the following compounds and classify them into primary, secondary and tertiary amines.
(i) (CH3 )2CHNH2 (ii) CH3 (CH2 )2NH2 (iii) CH3NHCH(CH3 )2
(iv) (CH3 )3CNH2 (v) C6H5NHCH3 (vi) (CH3CH2 )2NCH3 (vii) m–BrC6H4NH2
Give one chemical test to distinguish between the following pairs of compounds.
(i) Methylamine and dimethylamine
(ii) Secondary and tertiary amines
(iii) Ethylamine and aniline
(iv) Aniline and benzylamine
(v) Aniline and N-methylaniline
Account for the following:
(i) pKb of aniline is more than that of methylamine.
(ii) Ethylamine is soluble in water whereas aniline is not.
(iii) Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
(iv) Although amino group is o– and p– directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.
(v) Aniline does not undergo Friedel-Crafts reaction.
(vi) Diazonium salts of aromatic amines are more stable than those of aliphatic amines. (vii) Gabriel phthalimide synthesis is preferred for synthesising primary amines.
\(FeSO_4\) solution mixed with\( (NH_4)_2SO_4 \) solution in\( 1:1\) molar ratio gives the test of \(Fe^{2+}\) ion but \(CuSO_4\) solution mixed with aqueous ammonia in \( 1:4 \) molar ratio does not give the test of \(Cu^{2+}\) ion. Explain why?
Specify the oxidation numbers of the metals in the following coordination entities:
(i)\( [Co(H_2O)(CN)(en)_2] ^{2+}\)
(ii) \([CoBr_2(en)_2]^{+}\)
(iii)\( [PtCl_4]^{ 2–} \)
(iv) \(K_3[Fe(CN)_6]\)
(v) \([Cr(NH_3)_3Cl_3] \)