Using the property of determinants and without expanding, prove that: \(\begin{vmatrix}2&7&65\\3&8&75\\5&9&86\end{vmatrix}\)=0
\(\begin{vmatrix}2&7&65\\3&8&75\\5&9&86\end{vmatrix}\)
=\(\begin{vmatrix}2&7&63+2\\3&8&72+3\\5&9&81+5\end{vmatrix}\)
=\(\begin{vmatrix}2&7&63\\3&8&72\\5&9&81\end{vmatrix}+\begin{vmatrix}2&7&2\\3&8&3\\5&9&5\end{vmatrix}\)
=\(\begin{vmatrix}2&7&9(7)\\3&8&9(8)\\5&9&9(9)\end{vmatrix}+0\) [Two columns are identical]
=\(9\begin{vmatrix}2&7&7\\3&8&8\\5&9&9\end{vmatrix}\) [Two columns are identical]
=0
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.
Evaluate the determinants in Exercises 1 and 2.
\(\begin{vmatrix}2&4\\-5&-1\end{vmatrix}\)
Evaluate the determinants in Exercises 1 and 2.
(i) \(\begin{vmatrix}\cos\theta&-\sin\theta\\\sin\theta&\cos\theta\end{vmatrix}\)
(ii) \(\begin{vmatrix}x^2&-x+1&x-1\\& x+1&x+1\end{vmatrix}\)
Using properties of determinants,prove that:
\(\begin{vmatrix} x & x^2 & 1+px^3\\ y & y^2 & 1+py^3\\z&z^2&1+pz^3 \end{vmatrix}\)\(=(1+pxyz)(x-y)(y-z)(z-x)\)
Using properties of determinants,prove that:
\(\begin{vmatrix} 3a& -a+b & -a+c\\ -b+a & 3b & -b+c \\-c+a&-c+b&3c\end{vmatrix}\)\(=3(a+b+c)(ab+bc+ca)\)
Read More: Properties of Determinants