Step 1: Splitting the integral. The absolute value function \( |x| \) is defined as Splitting the integral at \( x = 0 \): \[ \int_{-1}^1 |x| \, dx = \int_{-1}^0 -x \, dx + \int_0^1 x \, dx \] Step 2: Evaluating the integrals. \[ \int_{-1}^0 -x \, dx = \left[ -\frac{x^2}{2} \right]_{-1}^0 = 0 - \left(-\frac{(-1)^2}{2}\right) = \frac{1}{2} \] \[ \int_0^1 x \, dx = \left[ \frac{x^2}{2} \right]_0^1 = \frac{1^2}{2} - 0 = \frac{1}{2} \] Step 3: Summing the results. \[ \int_{-1}^1 |x| \, dx = \frac{1}{2} + \frac{1}{2} = 1 \] Conclusion: Thus, the value of the integral is \( 1 \), which corresponds to option \( \mathbf{(C)} \).
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.