The stopping potential for photoelectric emission from a metal surface is plotted along Y-axis and frequency v of incident light along X-axis. A straight line is obtained as shown. Planck's constant is given by}
Show Hint
- slope of the line
- product of slope of the line and charge on the electron
- intercept along Y-axis divided by charge on the electron
- product of intercept along X-axis and mass of the electron
The Correct Option is B
Solution and Explanation
Einstein's photoelectric equation: $eV_s = h\nu - h\nu_0$.
Step 2: Detailed Explanation:
$V_s = \frac{h}{e}\nu - \frac{h\nu_0}{e}$. This is of the form $y = mx + c$, where slope $m = \frac{h}{e}$. Hence, $h = \text{slope} \times e$.
Step 3: Final Answer:
Planck's constant is the product of slope and electron charge.
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