Question:
At great distances from an electric dipole, the electric field strength due to the dipole varies with the distance as
At great distances from an electric dipole, the electric field strength due to the dipole varies with the distance as
Show Hint
The electric field of a dipole falls off as $1/r^3$, unlike a point charge which falls off as $1/r^2$.
Updated On: May 2, 2026
- $\frac{1}{r}$
- $\frac{1}{r^2}$
- $\frac{1}{r^3}$
- $\frac{1}{r^4}$
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept:
For an electric dipole, the electric field falls off faster than that of a point charge.
Step 2: Detailed Explanation:
For a dipole, the electric field at a distance $r$ along the axial line is $E = \frac{1}{4\pi\epsilon_0} \frac{2p}{r^3}$ for $r \gg$ dipole length. Hence, $E \propto \frac{1}{r^3}$.
Step 3: Final Answer:
The electric field varies as $\frac{1}{r^3}$.
For an electric dipole, the electric field falls off faster than that of a point charge.
Step 2: Detailed Explanation:
For a dipole, the electric field at a distance $r$ along the axial line is $E = \frac{1}{4\pi\epsilon_0} \frac{2p}{r^3}$ for $r \gg$ dipole length. Hence, $E \propto \frac{1}{r^3}$.
Step 3: Final Answer:
The electric field varies as $\frac{1}{r^3}$.
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