Question:

A photon and an electron have equal energy $E$. $\lambda_{\mathrm{photon}} / \lambda_{\mathrm{electron}}$ is proportional to

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de Broglie wavelength for electron: $\lambda = \frac{h}{\sqrt{2mE}}$.
Updated On: Apr 8, 2026
  • $\sqrt{E}$
  • $\frac{1}{\sqrt{E}}$
  • $\frac{1}{E}$
  • does not depend upon $E$
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
For photon, $\lambda_p = \frac{hc}{E}$. For electron, $\lambda_e = \frac{h}{\sqrt{2mE}}$.
Step 2: Detailed Explanation:
Ratio $\frac{\lambda_p}{\lambda_e} = \frac{hc/E}{h/\sqrt{2mE}} = c\sqrt{\frac{2m}{E}} \propto \frac{1}{\sqrt{E}}$.
Step 3: Final Answer:
The ratio is proportional to $\frac{1}{\sqrt{E}}$.
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