Question:

Photons of \(5.5\ \mathrm{eV}\) energy fall on the surface of the metal emitting photoelectrons of maximum kinetic energy \(4.0\ \mathrm{eV}\). The stopping voltage required for these electrons is

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Stopping potential is independent of light intensity and depends only on frequency.
Updated On: Apr 7, 2026
  • \(5.5\ \mathrm{V}\)
  • \(1.5\ \mathrm{V}\)
  • \(9.5\ \mathrm{V}\)
  • \(4.0\ \mathrm{V}\)
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept:
Stopping potential \(V_0\) satisfies \(eV_0 = \mathrm{K.E.}_{\max}\).
Step 2: Detailed Explanation:
\(\mathrm{K.E.}_{\max} = 4\ \mathrm{eV}\)
\(eV_0 = 4\ \mathrm{eV} \rightarrow V_0 = 4\ \mathrm{V}\)
Step 3: Final Answer:
Stopping voltage is 4.0 V.
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