Question:

The steady-state error of a Type 1 system for a unit step input is:

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Type 1 system → zero steady-state error for step input.
Updated On: May 20, 2026
  • Zero
  • Infinite
  • A non-zero constant
  • Oscillatory
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The Correct Option is A

Solution and Explanation

Concept: System type is defined by number of poles at origin.
• Type 0 → finite error for step
• Type 1 → zero error for step
• Type 2 → zero error for step and ramp

Step 1: Unit step input
\[ R(s) = \frac{1}{s} \]

Step 2: Error formula
\[ e_{ss} = \frac{1}{1 + K_p} \] For Type 1 system: \[ K_p = \infty \] \[ e_{ss} = 0 \] \[ \therefore \text{Correct answer is (A)} \]
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