Question:
The radius of innermost orbit of an electron in the hydrogen atom is $0.53\,\text{\AA}$. Then, the radius of the 3rd electron orbit is:
The radius of innermost orbit of an electron in the hydrogen atom is $0.53\,\text{\AA}$. Then, the radius of the 3rd electron orbit is:
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Radius in Bohr model varies as $n^2$.
Updated On: Apr 24, 2026
- $1.59\,\text{\AA}$
- $2.38\,\text{\AA}$
- $0.53\,\text{\AA}$
- $4.77\,\text{\AA}$
- $9.54\,\text{\AA}$
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The Correct Option is D
Solution and Explanation
Concept:
• Bohr radius: \[ r_n = n^2 r_1 \]
Step 1: Given
\[ r_1 = 0.53\,\text{\AA}, \quad n = 3 \]
Step 2: Compute
\[ r_3 = 3^2 \times 0.53 = 9 \times 0.53 = 4.77\,\text{\AA} \] Final Conclusion:
Option (D)
• Bohr radius: \[ r_n = n^2 r_1 \]
Step 1: Given
\[ r_1 = 0.53\,\text{\AA}, \quad n = 3 \]
Step 2: Compute
\[ r_3 = 3^2 \times 0.53 = 9 \times 0.53 = 4.77\,\text{\AA} \] Final Conclusion:
Option (D)
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