Question:

In a hydrogen atom, the transition of an electron from the energy level, \(n_2 = \infty\) and \(n_1 = 3\) is the

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For any series, the shortest wavelength (series limit) corresponds to \(n_2 = \infty\).
Updated On: Apr 24, 2026
  • shortest wavelength of Paschen series
  • longest wavelength of Paschen series
  • shortest wavelength of Balmer series
  • longest wavelength of Balmer series
  • shortest wavelength of Bracket series
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept:
Spectral series in hydrogen: Lyman (n=1), Balmer (n=2), Paschen (n=3), Bracket (n=4), Pfund (n=5). Transition from higher \(n_2\) to fixed \(n_1\).

Step 2:
Detailed Explanation:
Here, \(n_1 = 3\), so the series is Paschen. Transition from \(n_2 = \infty\) to \(n_1 = 3\) gives the maximum energy and hence the shortest wavelength within the Paschen series.

Step 3:
Final Answer:
The transition corresponds to the shortest wavelength of the Paschen series.
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