Question:
In the hydrogen spectrum, the shortest wavelength of the Brackett series is produced during the transition:
In the hydrogen spectrum, the shortest wavelength of the Brackett series is produced during the transition:
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Shortest wavelength = Series Limit = Transition from $n = \infty$.
Updated On: Apr 28, 2026
- $n_{2}=5$ and $n_{1}=4$
- $n_{2}=4$ and $n_{1}=1$
- $n_{2}=4$ and $n_{1}=3$
- $n_{2}=\infty$ and $n_{1}=4$
- $n_{2}=4$ and $n_{1}=2$
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The Correct Option is D
Solution and Explanation
Step 1: Concept
For the Brackett series, the final state is $n_1 = 4$.
Step 2: Analysis
Shortest wavelength corresponds to the maximum energy transition.
Step 3: Conclusion
Maximum energy occurs when the electron transitions from $n_2 = \infty$ to $n_1 = 4$. Final Answer: (D)
For the Brackett series, the final state is $n_1 = 4$.
Step 2: Analysis
Shortest wavelength corresponds to the maximum energy transition.
Step 3: Conclusion
Maximum energy occurs when the electron transitions from $n_2 = \infty$ to $n_1 = 4$. Final Answer: (D)
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