To determine the number of corner points of the feasible region, let us analyze the constraints: 1. \(x \geq 0\):
This represents the region to the right of the \(y\)-axis, including the \(y\)-axis itself. 2. \(y \geq 0\):
This represents the region above the \(x\)-axis, including the \(x\)-axis itself. 3. \(x + y \geq 4\):
This represents the region above the line \(x + y = 4\).
Rearranging, \(y = 4 - x\), which has intercepts at \(x = 4\) and \(y = 4\).
The feasible region is the intersection of these constraints, which lies in the first quadrant (\(x \geq 0\), \(y \geq 0\)) and above the line \(x + y = 4\). The feasible region is unbounded but has two corner points:
Intersection of \(x + y = 4\) with \(x = 0\): \((0, 4)\), - Intersection of \(x + y = 4\) with \(y = 0\): \((4, 0)\). Hence, the number of corner points is \(2\), and the correct answer is (C).
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.
Assertion (A): A line in space cannot be drawn perpendicular to \( x \), \( y \), and \( z \) axes simultaneously.
Reason (R): For any line making angles \( \alpha, \beta, \gamma \) with the positive directions of \( x \), \( y \), and \( z \) axes respectively, \[ \cos^2\alpha + \cos^2\beta + \cos^2\gamma = 1. \]