To determine the number of corner points of the feasible region, let us analyze the constraints: 1. \(x \geq 0\):
This represents the region to the right of the \(y\)-axis, including the \(y\)-axis itself. 2. \(y \geq 0\):
This represents the region above the \(x\)-axis, including the \(x\)-axis itself. 3. \(x + y \geq 4\):
This represents the region above the line \(x + y = 4\).
Rearranging, \(y = 4 - x\), which has intercepts at \(x = 4\) and \(y = 4\).
The feasible region is the intersection of these constraints, which lies in the first quadrant (\(x \geq 0\), \(y \geq 0\)) and above the line \(x + y = 4\). The feasible region is unbounded but has two corner points:
Intersection of \(x + y = 4\) with \(x = 0\): \((0, 4)\), - Intersection of \(x + y = 4\) with \(y = 0\): \((4, 0)\). Hence, the number of corner points is \(2\), and the correct answer is (C).
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).