Question:

The mole fraction of a solute in 2.0 molal aqueous solution is :

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2 molal = 2 mol solute in 1000 g water (55.56 mol); x = 2/(2+55.56).
Updated On: Jun 15, 2026
  • 1.87
  • 0.347
  • 0.0347
  • 0.00347
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The Correct Option is C

Solution and Explanation

Concept: A 2.0 molal solution has 2.0 mol solute per 1 kg (1000 g) of water.
Step 1: Moles of water \(=\dfrac{1000}{18}=55.56\) mol.
Step 2: Mole fraction of solute \[x_{solute}=\dfrac{n_{solute}}{n_{solute}+n_{water}}=\dfrac{2.0}{2.0+55.56}=\dfrac{2.0}{57.56}=0.0347\]Answer: \(\boxed{0.0347}\), option (C).
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