Question:
The function \(f(x) = x - |x - x^2|\), \(-1 \le x \le 1\) is continuous on
The function \(f(x) = x - |x - x^2|\), \(-1 \le x \le 1\) is continuous on
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Absolute value does not affect continuity.
Updated On: Mar 23, 2026
- \([-1,1]\)
- \((-1,1)\)
- \([-1,1]-\{0\}\)
- (-1,1)-0
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The Correct Option is A
Solution and Explanation
Absolute value and polynomial functions are continuous everywhere.
Hence f(x) is continuous for all x∈[-1,1].
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