Step 1: f(x)=x³-1 is a polynomial, hence continuous everywhere, so statement I is true.
Step 2: Root of x³-1=0 is x=1, which is not in (-1,1).
Thus statement II is also true?
But root lies at boundary x=1, so statement II (“no root in (-1,1)”) is true.
However, question asks correctness: only continuity is being emphasized as sure property.