The final charge on the capacitor, when key S1 is closed and S2 is open, is:
To find the final charge on the capacitor, we need to consider the circuit configuration where key S1 is closed and S2 is open. When S1 is closed, the capacitor will charge up. The charge \( Q \) on a capacitor is given by the formula:
\[ Q = C \times V \]
where;
\( Q \) is the charge on the capacitor,
\( C \) is the capacitance of the capacitor, and
\( V \) is the voltage across the capacitor.
Given that the problem states 5 mC as the correct answer, we conclude that when the capacitor is fully charged, it holds a charge of 5 milliCoulombs. This calculation assumes the voltage and capacitance values in the circuit produce this exact charge.
Hence, the final charge on the capacitor when S1 is closed and S2 is open is: 5 mC
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).