To solve the problem, we need to identify the reaction that converts phenol to salicylic acid.
1. Understanding the Conversion:
Phenol has the formula C\(_6\)H\(_5\)OH, and salicylic acid is C\(_6\)H\(_4\)(OH)(COOH), a benzene ring with both a hydroxyl (-OH) and a carboxyl (-COOH) group. The conversion involves introducing a carboxyl group to the phenol ring, specifically at the ortho position relative to the hydroxyl group.
2. Evaluating Option C (Reimer-Tiemann Reaction):
The Reimer-Tiemann reaction involves treating phenol with chloroform (CHCl\(_3\)) and a strong base (e.g., KOH) to introduce an aldehyde group (-CHO) ortho to the hydroxyl group, forming salicylaldehyde (C\(_6\)H\(_4\)(OH)(CHO)). This does not directly yield salicylic acid, as the product is an aldehyde, not a carboxylic acid. Further oxidation would be needed, which is not part of the standard reaction. Thus, this option is incorrect.
3. Evaluating Option B (Friedel-Crafts Reaction):
The Friedel-Crafts reaction typically involves alkylation or acylation of an aromatic ring using a halogenated compound and a Lewis acid catalyst (e.g., AlCl\(_3\)). For phenol, the -OH group is strongly activating and ortho-para directing, but Friedel-Crafts acylation (e.g., with CO and HCl) to introduce a carboxyl group directly is not a standard method for salicylic acid synthesis. Moreover, the -OH group can react with the catalyst, complicating the reaction. This option is incorrect.
4. Evaluating Option A (Kolbe Reaction):
The Kolbe-Schmitt reaction (often referred to as the Kolbe reaction in this context) involves heating sodium phenoxide (C\(_6\)H\(_5\)ONa, formed from phenol and NaOH) with carbon dioxide (CO\(_2\)) under pressure at around 125°C, followed by acidification. This introduces a carboxyl group ortho to the phenoxide group, forming salicylic acid:
$ \text{C}_6\text{H}_5\text{ONa} + \text{CO}_2 \xrightarrow{\text{heat, pressure}} \text{C}_6\text{H}_4(\text{OH})(\text{COONa}) \xrightarrow{\text{H}^+} \text{C}_6\text{H}_4(\text{OH})(\text{COOH}) $
This is the standard industrial method for synthesizing salicylic acid from phenol, making this option correct.
5. Evaluating Option D (Coupling Reaction):
A coupling reaction typically refers to reactions like diazo coupling, where a diazonium salt reacts with an aromatic compound (e.g., phenol) to form azo dyes. This does not involve the formation of a carboxyl group or salicylic acid. Thus, this option is incorrect.
Final Answer:
The conversion of phenol to salicylic acid can be accomplished by the Kolbe reaction (option A).
Write IUPAC names of the following compounds and classify them into primary, secondary and tertiary amines.
(i) (CH3 )2CHNH2 (ii) CH3 (CH2 )2NH2 (iii) CH3NHCH(CH3 )2
(iv) (CH3 )3CNH2 (v) C6H5NHCH3 (vi) (CH3CH2 )2NCH3 (vii) m–BrC6H4NH2
Give one chemical test to distinguish between the following pairs of compounds.
(i) Methylamine and dimethylamine
(ii) Secondary and tertiary amines
(iii) Ethylamine and aniline
(iv) Aniline and benzylamine
(v) Aniline and N-methylaniline
Account for the following:
(i) pKb of aniline is more than that of methylamine.
(ii) Ethylamine is soluble in water whereas aniline is not.
(iii) Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
(iv) Although amino group is o– and p– directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.
(v) Aniline does not undergo Friedel-Crafts reaction.
(vi) Diazonium salts of aromatic amines are more stable than those of aliphatic amines. (vii) Gabriel phthalimide synthesis is preferred for synthesising primary amines.