Question

The code given below accepts five numbers and displays whether they are even or odd: 
Observe the following code carefully and rewrite it after removing all syntax and logical errors. 
Underline all the corrections made.

Hint:

Always check for syntax errors (e.g., missing colons or parentheses) and ensure the correct operators are used for logical conditions (e.g., `%` for even/odd checks).

Answer 1

Given Code:

def EvenOdd()
    for i in range(5):
        num=int(input("Enter a number")
        if num/2==0:
            print("Even")
        else:
            print("Odd")
EvenOdd()
    

Corrected Code:

def EvenOdd():  # Added colon at the function definition
    for i in range(5):  # No change
        num = int(input("Enter a number: "))  # Added a colon and closed the parenthesis
        if num % 2 == 0:  # Changed division '/' to modulus '%' for even check
            print("Even")  # No change
        else:
            print("Odd")  # No change
EvenOdd()  # No change
    

Corrections Made:

• Added a colon : after the function definition def EvenOdd().
• Fixed the missing colon in the input statement: input("Enter a number: ").
• Replaced the division operator / with the modulus operator % in the condition: if num % 2 == 0.