The chances of \( P \), \( Q \), and \( R \) getting selected as CEO of a company are in the ratio \( 4 : 1 : 2 \), respectively. The probabilities for the company to increase its profits from the previous year under the new CEO \( P \), \( Q \), or \( R \) are \( 0.3 \), \( 0.8 \), and \( 0.5 \), respectively.
If the company increased the profits from the previous year, find the probability that it is due to the appointment of \( R \) as CEO.
Step 1: Assign probabilities
Let: \[ P(E_1) = \frac{4}{7}, \quad P(E_2) = \frac{1}{7}, \quad P(E_3) = \frac{2}{7}. \] The probabilities of increased profits under each CEO are: \[ P(A | E_1) = 0.3, \quad P(A | E_2) = 0.8, \quad P(A | E_3) = 0.5. \]
Step 2: Apply Bayes' theorem
The probability that the profits increased due to \( R \) as CEO is: \[ P(E_3 | A) = \frac{P(E_3) P(A | E_3)}{P(E_1) P(A | E_1) + P(E_2) P(A | E_2) + P(E_3) P(A | E_3)}. \]
Step 3: Substitute the values
\[ P(E_3 | A) = \frac{\frac{2}{7} \cdot 0.5}{\frac{4}{7} \cdot 0.3 + \frac{1}{7} \cdot 0.8 + \frac{2}{7} \cdot 0.5}. \]
Simplify the denominator:
\[ P(E_3 | A) = \frac{\frac{2}{7} \cdot 0.5}{\frac{4}{7} \cdot 0.3 + \frac{1}{7} \cdot 0.8 + \frac{2}{7} \cdot 0.5} = \frac{\frac{1}{7}}{\frac{1.2}{7}} = \frac{1}{3}. \]
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).