Step 1: Understand the problem
We need to find the area of the region bounded by the curve y = x, the x-axis, and the vertical lines x = 0 and x = 2.
Step 2: Set up the integral for the area
The area under the curve y = x from x = 0 to x = 2 is given by the definite integral:
Area = ∫ from 0 to 2 of x dx
Step 3: Calculate the integral
The integral of x with respect to x is (x²)/2.
So, Area = [ (x²)/2 ] evaluated from 0 to 2.
Step 4: Evaluate the definite integral
Substitute the upper limit x = 2:
(2)² / 2 = 4 / 2 = 2
Substitute the lower limit x = 0:
(0)² / 2 = 0
So, Area = 2 - 0 = 2 square units.
Step 5: Conclusion
The area of the region bounded by the curve y = x, the x-axis, x = 0 and x = 2 is 2 square units.
Final Answer: (C) 2
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).