Old ratio of Sameer and Sohan = 4 : 3
$\Rightarrow$ Total parts = 4 + 3 = 7
Sameer’s old share = $\dfrac{4}{7}$
Sohan’s old share = $\dfrac{3}{7}$
New profit sharing ratio among Sameer, Sohan, and Sudarshan = 2 : 3 : 2
$\Rightarrow$ Total parts = 2 + 3 + 2 = 7
Sameer’s new share = $\dfrac{2}{7}$
Sohan’s new share = $\dfrac{3}{7}$
Sudarshan’s new share = $\dfrac{2}{7}$
Now, compute the sacrifice = Old Share – New Share
Sohan’s old share = $\dfrac{3}{7} = \dfrac{9}{21}$
Sohan’s new share = $\dfrac{3}{7} = \dfrac{9}{21}$
$\Rightarrow$ Sohan’s sacrifice = $\dfrac{9}{21} - \dfrac{9}{21} = 0$
But since the question mentions a change to a new ratio 2 : 3 : 2, and if that was actually meant to be a sacrifice by both partners, we must calculate the sacrifice ratio:
Old Ratio = Sameer : Sohan = 4 : 3
New Ratio = Sameer : Sohan : Sudarshan = 2 : 3 : 2
Let’s convert both to 21 parts for easy comparison:
Old Ratio: Sameer = $\dfrac{4}{7} = \dfrac{12}{21}$, Sohan = $\dfrac{3}{7} = \dfrac{9}{21}$
New Ratio: Sameer = $\dfrac{2}{7} = \dfrac{6}{21}$, Sohan = $\dfrac{3}{7} = \dfrac{9}{21}$, Sudarshan = $\dfrac{2}{7} = \dfrac{6}{21}$
Sohan’s share remains unchanged, so no sacrifice.
$\Rightarrow$ Correct answer is (A) Nil, although if Sudarshan received some share from Sohan alone, a clarification in the question would be needed.

A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).