Propene to 1-Iodopropane
To convert propene to 1-iodopropane, hydroiodic acid (HI) is used in an electrophilic addition reaction.
The double bond in propene reacts with HI. According to Markovnikov's rule, the hydrogen atom from HI attaches to the carbon with more hydrogen atoms, and the iodine attaches to the other carbon, forming the desired product.
\( \text{CH}_2=\text{CHCH}_3 + \text{HI} \rightarrow \text{CH}_3\text{CH}_2\text{CH}_2\text{I} \)
Product: 1-iodopropane
The major product (A) is:

A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).