Question

Match the ion (LIST-I) and their Gram equivalent weight (LIST-II): [H] {|l|l|l|l|} \multicolumn{2}{|c|}{LIST-I & \multicolumn{2}{c|}{LIST-II
\multicolumn{2}{|c|}{(Ion) & \multicolumn{2}{c|}{(Gram equivalent weight)
A. & Phosphate $(\text{HPO}_4)^{-2}$ & I. & 39
B. & Bicarbonate $(\text{HCO}_3)^{-1}$ & II. & 20
C. & Calcium $(\text{Ca})^{+2}$ & III. & 48
D. & Potassium $(\text{K})^{+1}$ & IV. & 61

• A. A-II, B-IV, C-III, D-I
• B. A-III, B-IV, C-II, D-I
• C. A-III, B-I, C-II, D-IV
• D. A-III, B-IV, C-I, D-II

Hint:

Equivalent Weight = Molecular Weight Valency.

Answer 1

The Correct Option is B

Step 1: Concept
Gram equivalent weight is calculated as the atomic or molecular weight divided by the valence of the ion.

Step 2: Meaning
A. Phosphate $(HPO_{4})^{-2}$ has a molecular weight of ~96; with valence 2, Eq Wt is 48. B. Bicarbonate $(HCO_{3})^{-1}$ has a molecular weight of ~61; with valence 1, Eq Wt is 61. C. Calcium $(Ca)^{+2}$ has an atomic weight of 40; with valence 2, Eq Wt is 20. D. Potassium $(K)^{+1}$ has an atomic weight of 39; with valence 1, Eq Wt is 39.

Step 3: Analysis
Matching the values: A-III (48), B-IV (61), C-II (20), and D-I (39).

Step 4: Conclusion
The correct matching sequence is A-III, B-IV, C-II, D-I.

Final Answer: (B)