Question:

Match the LIST-I with LIST-II. 

LIST-ILIST-II
A. All human beings are mortalI. \( (\exists x)(Hx \cdot Mx) \)
B. No human beings are mortalII. \( (\exists x)(Hx \cdot \sim Mx) \)
C. Some human beings are mortalIII. \( (x)(Hx \supset Mx) \)
D. Some human beings are not mortalIV. \( (x)(Hx \supset \sim Mx) \)

Choose the correct answer from the options given below.

Show Hint

Universal statements use \((x)\), while particular statements use \((\exists x)\).
Updated On: May 30, 2026
  • A-III, B-IV, C-I, D-II
  • A-I, B-II, C-III, D-IV
  • A-III, B-II, C-IV, D-I
  • A-IV, B-III, C-II, D-I
Show Solution
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The Correct Option is A

Solution and Explanation

Concept:
In predicate logic, universal propositions are represented with the universal quantifier, and particular propositions are represented with the existential quantifier. Here: \[ Hx = x \text{ is a human being} \] \[ Mx = x \text{ is mortal} \]

Step 1:
Translate A.
\[ \text{All human beings are mortal} \] This means: \[ (x)(Hx \supset Mx) \] So: \[ A \rightarrow III \]

Step 2:
Translate B.
\[ \text{No human beings are mortal} \] This means: \[ (x)(Hx \supset \sim Mx) \] So: \[ B \rightarrow IV \]

Step 3:
Translate C.
\[ \text{Some human beings are mortal} \] This means: \[ (\exists x)(Hx \cdot Mx) \] So: \[ C \rightarrow I \]

Step 4:
Translate D.
\[ \text{Some human beings are not mortal} \] This means: \[ (\exists x)(Hx \cdot \sim Mx) \] So: \[ D \rightarrow II \]

Step 5:
Final matching.
The correct matching is: \[ A-III,\ B-IV,\ C-I,\ D-II \] Hence: \[ \boxed{\text{(A)}} \]
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