| Date | Particulars | L.F. | Dr. (₹) | Cr. (₹) |
|---|---|---|---|---|
| Equity Share Capital A/c Dr. (2,000 × ₹10) To Share Forfeiture A/c To Calls-in-Arrears A/c (First & Final Call) (Being 2,000 shares forfeited for non-payment of first & final call of ₹2 per share) | 20,000 | 16,000 4,000 | ||
| Bank A/c (Ashok) Dr. Share Forfeiture A/c Dr. To Equity Share Capital A/c (750 × ₹10) To Securities Premium A/c (Being 750 forfeited shares re-issued to Ashok as fully paid-up) | 10,000 2,000 | 7,500 4,500 | ||
| Bank A/c (Sudha) Dr. Share Forfeiture A/c Dr. To Equity Share Capital A/c (1,250 × ₹10) (Being 1,250 forfeited shares re-issued to Sudha at ₹9 per share fully paid-up) | 11,250 1,250 | 12,500 | ||
| Share Forfeiture A/c Dr. To Capital Reserve A/c (Being profit on re-issue transferred to Capital Reserve) | 12,750 | 12,750 |
Face Value per Share = ₹10 First & Final Call = ₹2 Amount received per share before forfeiture: \[ 10 - 2 = 8 \] Total amount received: \[ 2,000 \times 8 = 16,000 \] ---
\[ 2,000 \times 10 = 20,000 \] Calls-in-arrears: \[ 2,000 \times 2 = 4,000 \] Share Forfeiture credited = ₹16,000 ---
Amount received: \[ ₹10,000 \] Face value: \[ 750 \times 10 = 7,500 \] Balance treated as premium: \[ 10,000 - 7,500 = 2,500 \] Share Forfeiture adjusted: \[ 2,000 \] ---
Amount received: \[ 1,250 \times 9 = 11,250 \] Face value: \[ 1,250 \times 10 = 12,500 \] Discount on re-issue: \[ 12,500 - 11,250 = 1,250 \] Share Forfeiture available: \[ \frac{1,250}{2,000} \times 16,000 = 10,000 \] ---
| Particulars | Amount (₹) | Particulars | Amount (₹) |
|---|---|---|---|
| To Ashok (Re-issue) | 2,000 | By Balance b/d | 16,000 |
| To Sudha (Re-issue) | 1,250 | ||
| To Capital Reserve | 12,750 | ||
| Total | 16,000 | Total | 16,000 |
---
\[ 16,000 - 2,000 - 1,250 = 12,750 \] Transferred to Capital Reserve = ₹12,750
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).