Question:
In Bohr model, for large $n$, spacing between consecutive orbits is proportional to
In Bohr model, for large $n$, spacing between consecutive orbits is proportional to
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Always expand $(n+1)^2 - n^2$ for spacing questions.
Updated On: Jul 2, 2026
- $\sqrt{n}$
- $n$
- $n^2$
- $n^3$
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The Correct Option is B
Solution and Explanation
Bohr radius:
\[
r_n = n^2 a_0
\]
Step 1: Distance between consecutive orbits \[ \Delta r = r_{n+1} - r_n \] \[ = (n+1)^2 a_0 - n^2 a_0 \] \[ = (2n+1)a_0 \]
Step 2: For large $n$ \[ \Delta r \approx 2n a_0 \propto n \] Final Answer: \[ \boxed{(B)} \]
Step 1: Distance between consecutive orbits \[ \Delta r = r_{n+1} - r_n \] \[ = (n+1)^2 a_0 - n^2 a_0 \] \[ = (2n+1)a_0 \]
Step 2: For large $n$ \[ \Delta r \approx 2n a_0 \propto n \] Final Answer: \[ \boxed{(B)} \]
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