Question:

In a plane wall under steady-state one-dimensional conduction with no heat generation, the temperature profile is ______.

Show Hint

The temperature profile shape depends directly on the geometry of the solid:
- Plane wall: Linear profile.
- Hollow cylinder (pipe): Logarithmic profile.
- Hollow sphere: Hyperbolic (proportional to $1/r$) profile.
Updated On: Jun 30, 2026
  • Linear
  • Exponential
  • Logarithmic
  • Sinusoidal
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Question:
The question asks for the mathematical shape of the temperature distribution profile across a flat (plane) wall experiencing steady-state, one-dimensional conductive heat transfer with constant thermal conductivity and no internal heat source.

Step 2: Key Formula or Approach:

Fourier's Law of heat conduction in one dimension is:
\[ q = -k A \frac{dT}{dx} \] where:
$q$ = heat transfer rate ($\text{W}$),
$k$ = thermal conductivity ($\text{W/m}\cdot\text{K}$),
$A$ = cross-sectional area perpendicular to heat flow ($\text{m}^2$),
$\frac{dT}{dx}$ = temperature gradient in the direction of distance $x$.

Step 3: Detailed Explanation:


Steady-State Conditions: Under steady-state conditions, the temperature at any position $x$ is constant over time, meaning the heat transfer rate ($q$) passing through the wall remains constant.

No Heat Generation: With no internal heat generation and assuming constant thermal conductivity ($k$) and cross-sectional area ($A$), we can rearrange Fourier's Law as:
\[ \frac{dT}{dx} = -\frac{q}{k A} = \text{Constant} \]
Integration: Integrating this differential equation with respect to distance $x$:
\[ \int dT = \int \left( -\frac{q}{k A} \right) dx \] \[ T(x) = C_1 x + C_2 \] where $C_1 = -\frac{q}{k A}$ and $C_2$ is the integration constant defined by boundary conditions.

Profile Analysis: This is the equation of a straight line ($y = mx + c$). Consequently, the temperature decreases uniformly and linearly with distance through the plane wall.

Step 4: Final Answer:

Under steady-state, one-dimensional conduction with no heat generation, the temperature profile across a plane wall is linear, making option (A) the correct choice.
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