Step 1: Find the dot product of \( \vec{a} \) and \( \vec{b} \)
The dot product of \( \vec{a} \) and \( \vec{b} \) is: \[ \vec{a} \cdot \vec{b} = (2)(1) + (-1)(1) + (1)(-1) = 2 - 1 - 1 = 0. \]
Step 2: Check for perpendicularity
If \( \vec{a} \cdot \vec{b} = 0 \), the vectors are perpendicular.
Step 3: Conclude the result
The vectors \( \vec{a} \) and \( \vec{b} \) are perpendicular.
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.
ABCD is a parallelogram. If \( \vec{AB} = 2\hat{i} - 4\hat{j} + 5\hat{k} \) and \( \vec{DB} = 3\hat{i} - 6\hat{j} + 2\hat{k} \), then find \( \vec{AD} \) and hence find the area of parallelogram ABCD.