Question:
If transistor having \(α = 0.9\), is used in CE configuration, then for a change of \(0.4\) mA in base current, what will be the change in collector current?
If transistor having \(α = 0.9\), is used in CE configuration, then for a change of \(0.4\) mA in base current, what will be the change in collector current?
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\(\beta=\frac{\alpha}{1-\alpha}\) and \(\Delta I_C=\beta\Delta I_B\).
Updated On: Oct 1, 2026
- \(3.6\) mA
- \(4\) mA
- \(0.9\) mA
- \(36\) mA
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept:
The current gain in CE configuration is \(\beta = \frac{\Delta I_C}{\Delta I_B}\), and it is linked to \(\alpha\) by \(\beta = \frac{\alpha}{1-\alpha}\).
Step 2: Calculate:
\(\beta = \frac{0.9}{0.1} = 9\).
\[ \Delta I_C = \beta\,\Delta I_B = 9\times0.4 = 3.6\ \text{mA} \]
Final Answer:
The change in collector current is \(3.6\) mA, option (A). \[ \boxed{3.6\ \text{mA}} \]
The current gain in CE configuration is \(\beta = \frac{\Delta I_C}{\Delta I_B}\), and it is linked to \(\alpha\) by \(\beta = \frac{\alpha}{1-\alpha}\).
Step 2: Calculate:
\(\beta = \frac{0.9}{0.1} = 9\).
\[ \Delta I_C = \beta\,\Delta I_B = 9\times0.4 = 3.6\ \text{mA} \]
Final Answer:
The change in collector current is \(3.6\) mA, option (A). \[ \boxed{3.6\ \text{mA}} \]
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