Question:
According to Einstein's photoelectric equation, the graph of the kinetic energy of the emitted photoelectrons versus the frequency of incident radiation gives a straight line whose slope
According to Einstein's photoelectric equation, the graph of the kinetic energy of the emitted photoelectrons versus the frequency of incident radiation gives a straight line whose slope
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From K = h nu - phi, the slope is Planck's constant.
Updated On: Oct 1, 2026
- depends on the intensity of incident radiation.
- depends on the nature of the metal used.
- is the same for all metals and independent of the intensity of radiation.
- depends on both the intensity of incident radiation and the nature of metal used.
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The Correct Option is C
Solution and Explanation
Step 1: Einstein's Equation:
\(K_{max}=h\nu-\phi\). Plotting \(K_{max}\) on the y-axis against \(\nu\) on the x-axis gives a straight line \(y=mx+c\).
Step 2: Slope and Intercept:
The slope is \(h\), Planck's constant. The intercept on the y-axis is \(-\phi\), which depends on the metal. The intercept on the frequency axis is the threshold frequency.
Step 3: Check the Statements:
The slope \(h\) is a universal constant, so it is the same for all metals. Intensity changes only the number of photoelectrons, not the \(K_{max}\)-versus-frequency line. So (C) is correct and (A), (B), (D) are not.
Final Answer:
The slope is the same for all metals and independent of intensity, option (C). \[ \boxed{\text{(C)}} \]
\(K_{max}=h\nu-\phi\). Plotting \(K_{max}\) on the y-axis against \(\nu\) on the x-axis gives a straight line \(y=mx+c\).
Step 2: Slope and Intercept:
The slope is \(h\), Planck's constant. The intercept on the y-axis is \(-\phi\), which depends on the metal. The intercept on the frequency axis is the threshold frequency.
Step 3: Check the Statements:
The slope \(h\) is a universal constant, so it is the same for all metals. Intensity changes only the number of photoelectrons, not the \(K_{max}\)-versus-frequency line. So (C) is correct and (A), (B), (D) are not.
Final Answer:
The slope is the same for all metals and independent of intensity, option (C). \[ \boxed{\text{(C)}} \]
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