Question:
In an n-p-n transistor in common emitter configuration when \(V_{BE}\) is increased by small amount then
In an n-p-n transistor in common emitter configuration when \(V_{BE}\) is increased by small amount then
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A larger base-emitter forward bias raises the base current, and the collector current follows it.
Updated On: Nov 12, 2026
- \(I_{B}\) increases and \(I_{C}\) increases proportionally
- \(I_{B}\) increases and \(I_{C}\) remain constant
- \(I_{B}\) remain constant and \(I_{C}\) increases
- both \(I_{B}\) and \(I_{C}\) remain nearly constant
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept
In a common emitter n-p-n transistor the base-emitter junction is forward biased and the collector current is controlled by the base current.
Step 2: Effect of Increasing V_BE
A small rise in \(V_{BE}\) increases the forward bias, so more carriers cross the junction and \(I_B\) rises.
Step 3: Collector Current
The collector current follows from \(I_C=\beta I_B\), so \(I_C\) rises in proportion to \(I_B\).
Step 4: Compare the options
Option (A) matches this behaviour.
Final Answer:
Both the base current and the collector current increase, the collector current in proportion. \[ \boxed{\text{(A) }I_{B}\text{ increases and }I_{C}\text{ increases proportionally}} \]
In a common emitter n-p-n transistor the base-emitter junction is forward biased and the collector current is controlled by the base current.
Step 2: Effect of Increasing V_BE
A small rise in \(V_{BE}\) increases the forward bias, so more carriers cross the junction and \(I_B\) rises.
Step 3: Collector Current
The collector current follows from \(I_C=\beta I_B\), so \(I_C\) rises in proportion to \(I_B\).
Step 4: Compare the options
Option (A) matches this behaviour.
Final Answer:
Both the base current and the collector current increase, the collector current in proportion. \[ \boxed{\text{(A) }I_{B}\text{ increases and }I_{C}\text{ increases proportionally}} \]
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