Question:
For a transistor, the current ratio \(\alpha _{DC}=\frac{69}{70}\). The current gain \(\beta _{DC}\) is
For a transistor, the current ratio \(\alpha _{DC}=\frac{69}{70}\). The current gain \(\beta _{DC}\) is
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Use the relation beta = alpha divided by (1 - alpha).
Updated On: Nov 12, 2026
- \(66\)
- \(67\)
- \(69\)
- \(71\)
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept
For a transistor the d.c. current gains are related by \(\beta_{DC}=\dfrac{\alpha_{DC}}{1-\alpha_{DC}}\).
Step 2: Substitute
With \(\alpha_{DC}=\dfrac{69}{70}\), \(1-\alpha_{DC}=\dfrac{1}{70}\).
Step 3: Calculation
\(\beta_{DC}=\dfrac{69/70}{1/70}=69\).
Step 4: Compare the options
This is option (C).
Final Answer:
The current gain beta is 69. \[ \boxed{\text{(C) }69} \]
For a transistor the d.c. current gains are related by \(\beta_{DC}=\dfrac{\alpha_{DC}}{1-\alpha_{DC}}\).
Step 2: Substitute
With \(\alpha_{DC}=\dfrac{69}{70}\), \(1-\alpha_{DC}=\dfrac{1}{70}\).
Step 3: Calculation
\(\beta_{DC}=\dfrac{69/70}{1/70}=69\).
Step 4: Compare the options
This is option (C).
Final Answer:
The current gain beta is 69. \[ \boxed{\text{(C) }69} \]
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