Question:

If the length of the span between two level supports is increased by \(20\%\), the sag will increase by approximately

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Sag is proportional to the square of span length. If span becomes \(1.2\) times, sag becomes \(1.44\) times.
Updated On: May 27, 2026
  • \(20\%\)
  • \(40\%\)
  • \(44\%\)
  • \(50\%\)
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The Correct Option is C

Solution and Explanation

Concept: For a transmission line conductor between level supports, sag is approximately: \[ S=\frac{wL^2}{8T} \] where \(L\) is span length.

Step 1:
From the sag formula: \[ S\propto L^2 \]

Step 2:
If span length is increased by \(20\%\), then: \[ L'=1.2L \]

Step 3:
New sag: \[ S'\propto (L')^2 \] \[ S'\propto (1.2L)^2 \] \[ S'=1.44S \]

Step 4:
Increase in sag: \[ S'-S=1.44S-S=0.44S \] \[ \text{Percentage increase}=44\% \] Therefore: \[ \boxed{44\%} \]
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