Question

If the area under a \(24\) hour daily load curve is \(480\ \text{MWh}\). The average load for that day is

• A. \(10\ \text{MW}\)
• B. \(20\ \text{MW}\)
• C. \(40\ \text{MW}\)
• D. \(480\ \text{MW}\)

Hint:

Area under load curve gives energy. Average load \(=\frac{\text{Energy}}{\text{Time}}\).

Answer 1

The Correct Option is B

Concept: Average load is: \[ \text{Average load}=\frac{\text{Energy consumed}}{\text{Time}} \]

Step 1: Given energy consumed in 24 hours: \[ E=480\ \text{MWh} \]

Step 2: Time duration: \[ t=24\ \text{h} \]

Step 3: Average load: \[ P_{\text{avg}}=\frac{480}{24} \] \[ P_{\text{avg}}=20\ \text{MW} \] Therefore: \[ \boxed{20\ \text{MW}} \]