Question

If soil resistance is 0.6 $Kg/cm^{2}$ and width of plough is 120cm, depth 10cm then draft is

• A. 72 kg
• B. 720kg
• C. 1420kg
• D. 7200kg

Hint:

Draft = (Force per unit area) $\times$ (Width $\times$ Depth). It's just the volume of soil being moved multiplied by its "toughness."

Answer 1

The Correct Option is B

Step 1: Concept
Draft is the total force required to pull an implement, calculated as: $\text{Draft} = \text{Specific Resistance} \times \text{Cross-sectional Area of Furrow}$.

Step 2: Meaning
Area = Width $\times$ Depth = $120~cm \times 10~cm = 1200~cm^{2}$.

Step 3: Analysis
$\text{Draft} = 0.6~Kg/cm^{2} \times 1200~cm^{2}$.

Step 4: Conclusion
$0.6 \times 1200 = 720~kg$.
Final Answer: (B)