To maximize a linear objective function:
1. Identify all vertices of the feasible region.
2. Substitute the coordinates of each vertex into the objective function.
3. Choose the highest value for maximization.
Step 1: The objective function \( z = 5x + 2y \) is maximized at one of the vertices of the feasible region \( R_1 \). The vertices of \( R_1 \) are \( A(0, 50) \), \( B(20, 40) \), and \( C(50, 100) \).
Step 2: Evaluate \( z \) at each vertex: - At \( A(0, 50) \): \[ z = 5(0) + 2(50) = 100. \] - At \( B(20, 40) \): \[ z = 5(20) + 2(40) = 100 + 80 = 180. \] - At \( C(50, 100) \): \[ z = 5(50) + 2(100) = 250 + 200 = 450. \]
Step 3: Conclusion: The maximum value of \( z = 5x + 2y \) is 450 at \( C(50, 100) \).
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).