Expand the left-hand side of the given equation: \[ (A + B)^2 = A^2 + AB + BA + B^2. \]
Equating both sides: \[ A^2 + AB + BA + B^2 = A^2 + B^2. \]
Cancel \( A^2 \) and \( B^2 \): \[ AB + BA = 0. \]
Rearranging: \[ AB = -BA. \]
Therefore, the correct answer is (B) \( AB = -BA \).
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.
\[ \begin{bmatrix} x + y & 2 \\ 5 & xy \end{bmatrix} = \begin{bmatrix} 6 & 2 \\ 5 & 8 \end{bmatrix}, \]
then the value of\[ \left(\frac{24}{x} + \frac{24}{y}\right) \]
is: