Question:
Identify the product \(P\) from the following sequence of reactions.
Identify the product \(P\) from the following sequence of reactions.
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Grignard reagent adds to ketones to form tertiary alcohols. Tertiary alcohols on dehydration give alkenes, and alkenes on hydrogenation give alkanes.
Updated On: Jun 26, 2026
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The Correct Option is A
Solution and Explanation
Step 1: Reaction with Grignard reagent.
Cyclopentanone reacts with methyl magnesium bromide: \[ CH_3MgBr \] The methyl group attacks the carbonyl carbon of cyclopentanone.
After acidic hydrolysis, \[ H_3O^+ \] a tertiary alcohol is formed.
Thus, the first product is \[ 1\text{-methylcyclopentanol} \]
Step 2: Dehydration of alcohol.
On heating with concentrated sulphuric acid, \[ Conc.\ H_2SO_4/\Delta \] the alcohol undergoes dehydration.
Loss of water gives an alkene: \[ 1\text{-methylcyclopentene} \]
Step 3: Hydrogenation of alkene.
The alkene reacts with hydrogen in the presence of platinum: \[ H_2/Pt \] This hydrogenates the double bond and gives the corresponding alkane: Methylcyclopentane
Step 4: Final conclusion.
Therefore, the product \(P\) is \[ \boxed{\text{Methylcyclopentane}} \] Hence, the correct option is \[ \boxed{(1)} \]
Cyclopentanone reacts with methyl magnesium bromide: \[ CH_3MgBr \] The methyl group attacks the carbonyl carbon of cyclopentanone.
After acidic hydrolysis, \[ H_3O^+ \] a tertiary alcohol is formed.
Thus, the first product is \[ 1\text{-methylcyclopentanol} \]
Step 2: Dehydration of alcohol.
On heating with concentrated sulphuric acid, \[ Conc.\ H_2SO_4/\Delta \] the alcohol undergoes dehydration.
Loss of water gives an alkene: \[ 1\text{-methylcyclopentene} \]
Step 3: Hydrogenation of alkene.
The alkene reacts with hydrogen in the presence of platinum: \[ H_2/Pt \] This hydrogenates the double bond and gives the corresponding alkane: Methylcyclopentane
Step 4: Final conclusion.
Therefore, the product \(P\) is \[ \boxed{\text{Methylcyclopentane}} \] Hence, the correct option is \[ \boxed{(1)} \]
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