Question:

Ethanal \(\xrightarrow{i. (CH_3)_2CHMgBr,\ ii.\ H_2O}\) X;
Propanone \(\xrightarrow{i.\ C_2H_5MgBr,\ ii.\ H_2O}\) Y.
Consider statements: I. Ease of dehydration \(Y>X\); II. Acidic character \(X>Y\); III. Reactivity towards Lucas reagent \(X>Y\). I. Ease of dehydration is Y > X
II. Acidic character is X > Y
III. Reactivity towards Lucas reagent is X > Y

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Lucas reagent test follows the order: \[ 3^\circ > 2^\circ > 1^\circ \] because tertiary carbocations form most easily.
Updated On: Jun 8, 2026
  • I, II only
  • I, III only
  • II, III only
  • I, II, III
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The Correct Option is A

Solution and Explanation

Concept: Grignard reagents convert aldehydes and ketones into alcohols.

Step 1: Identify X and Y.
Ethanal reacts with isopropyl magnesium bromide to form a secondary alcohol: \[ X = \text{secondary alcohol} \] Propanone reacts with ethyl magnesium bromide to form a tertiary alcohol: \[ Y = \text{tertiary alcohol} \]

Step 2: Evaluate statement I.
Tertiary alcohols dehydrate more easily: \[ Y > X \] Statement I is correct.

Step 3: Evaluate statement II.
Secondary alcohols are slightly more acidic than tertiary alcohols due to lesser electron donating effect. Hence: \[ X > Y \] Statement II is correct.

Step 4: Evaluate statement III.
Lucas reagent reacts faster with tertiary alcohols: \[ Y > X \] Thus statement III is incorrect. Hence, correct statements are: \[ \boxed{I,\ II\ only} \]
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